Answer:
Step-by-step explanation:
The given equation is expressed as
x1 + 2x2 = -24- - - - - - - - --1
x1 + 7x2 = -11- - - - - - - --2
We would eliminate x1 by subtracting equation 2 from equation 1. It becomes
- 5x2 = - 13
Dividing both sides of the equation by - 5, it becomes
- 5x2/- 5 = - 13/- 5
x2 = 13/5
Substituting x2 = 13/5 into equation 2, it becomes
x1 + 7 × 13/5 = -11
x1 + 91/5 = - 11
x1 = - 11 - 91/5
x1 = - 146/5
(2,0) (5.0) (5,3) (2,3)
(2,0) (-1,0) (2,3) (-1,3)
Answer: 5.37
Step-by-step explanation:
Let x = ACT scores.
Given: ACT scores have a mean of 20.8 and 9 percent of the scores are above 28. The scores have a distribution that is approximately normal.
i.e. P(X>28)=0.09 (i)
Now,
![P(X>28)=P(\dfrac{X-\mu}{\sigma}>\dfrac{28-20.8}{\sigma})\\\\= P(z>\dfrac{7.2}{\sigma})\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]](https://tex.z-dn.net/?f=P%28X%3E28%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B28-20.8%7D%7B%5Csigma%7D%29%5C%5C%5C%5C%3D%20P%28z%3E%5Cdfrac%7B7.2%7D%7B%5Csigma%7D%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D)
(ii)
One -tailed z value for p-value of 0.09 =1.3408 [By z-table]
From (i) and (ii)
Hence, the standard deviation = 5.37
<span>y=x-4
y=-x+6
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Substitute x - 4 for y in </span>y=-x+6
x-4=-x+6<span>
--------------------------------
Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
--------------------------------------
Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
================================================================
To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
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Your answers are Y = 1 and X = 5
Answer:
558/1
Step-by-step explanation:
