All categories

3 years ago

Which of these are mathematical laws that help us solve numerical problems? decimals graphs formulas percentages fractions

2 answers:

6 0

Formulas are mathematical laws that help us solve problems.

Decimals are a type of number; graphs are displays of data; percentages are comparisons of a number to 100; and fractions are a type of number.

photoshop1234 [79]3 years ago

5 0

Answer:

The mathematical laws that help us to solve numerical problems are:

Formulas.

Step-by-step explanation:

Decimals--

The decimals is just a numeral system which is used to represent an integer or an non-integer value.

Graphs--

The graphs are just a visual display of the data values in the coordinate plane.

Formulas--

It is just a mathematical rule that is expressed in numerals or some other symbols and is used to solve a numerical problem.

Percentage--

In mathematics, a percentage is a number or a ratio expressed as a fraction of 100.

Fractions--

A fraction represent a part of something as a whole.

for example--

If a spinner has four sections of equal parts with different colors,.

Then the fraction of one part of the spinner is:

1/4

You might be interested in

Matt charges 3$ for every 15$of walking . how much will matt charge for one hour

IRINA_888 [86]

5 dollars per hour
because 15 divided by 3 is 5.

8 0

3 years ago

Read 2 more answers

What does X equal 9.6x − 15.4 = −4.4x − 11.2 A.) x = 0.3 B.)x=−0.3 C.) x = −3 D.) x = 3

sweet [91]

The answer is A) x=0.3

Step-by-step explanation:

Move all terms containing xx to the left side of the equation.

14x−15.4=−11.2

Move all terms not containing x to the right side of the equation.

14x=4.214x=4.2

Divide each term by 14 and simplify

x=0.3

3 0

3 years ago

Needs to be checked.............

Lubov Fominskaja [6]

B. is the correct answer you got it right

Malory your fellow helper

7 0

3 years ago

Read 2 more answers

Given the points (5, 5) and (3, 7), write a linear equation that contains both in slope-intercept form.

zlopas [31]

First find slope
(7-5)/(3-5) = 2/-2 = -1
Slope intercept: y = mx + b
Y = -1x + b, plug in point
5 = -1(5) + b, b = 10
Equation: y = -1x + 10

5 0

2 years ago

Read 2 more answers

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago