See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
<h3>How to graph the inequalities?</h3>
The inequalities are given as:
x + 7y ≤ 49
6x + y ≤ 48
The domain and the range are:
x ≥ 0
y ≥ 0
This means that, we plot the inequalities x + 7y ≤ 49 and 6x + y ≤ 48 under the domain and the range x ≥ 0 and y ≥ 0
See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
Read more about inequalities at:
brainly.com/question/25275758
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That is so confusing the way theyou word it sometimes is like what the...what?
Answer:
B. (6, 8)
Step-by-step explanation:
To figure this out, you can plug in the coordinates to see if you get matching answers. Since you believe answer "B," is correct, we can check:
y - 8 = -3(x - 6)
8 - 8 = -3(6 - 6)
0 = -3(0)
0 = 0
<u>Since the answers match, that makes answer "B," correct.</u>
Answer:
-4/6, or -2/3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
radius of wheel 
Time period of Wheel 
and
, where 

Let at any angle
with vertical position of a point is given by


and 
for velocity differentiate x and y to get


Height at any time t is given by
