Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
Step-by-step explanation:
first you do 3×1 get your answer and then × it by 2 then your answer you get you × it by 3 what you get - by 2 what you get you - by 1 and you get your answer hope I helped
Answer:
(6, 2), (0, -2), (-3, -4)
Step-by-step explanation:
The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.
Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.
(x-3)^2, as x-3 is repeated twice
150 = 5 classes
1 class = 30
