Which expression is equivalent to 880 • (10- 1/2)?

Two drugs were tested to see whether they helped women with breast cancer. Of 1060 women, about half were randomly assigned to

Arlecino [84]

Answer:

(a) The survival rate for drug A is 87,75%.

(b) The survival rate for drug B is 81,76%.

Step-by-step explanation:

To get the survival rate of each drug you have to divide the number of women alive between the total number of women that use the drug.

For drug A= women alive that use drug A/ total number of women that use the drug A= 473/539

For drug A=0,8775= 87,75%

For drug B= women alive that use drug B/ total number of women that use the drug B

For drug B== 426/521= 0,8176 = 81,76%

3 0

4 years ago

Y = 2x + 5 and 3x + y = 40

Sophie [7]

ANSWER: x=7, y=19

Steps

1. Substitute y=2x+5

3x+2x+5=40

2. For y=2x+5 , Substitute x=7

y=2 * 7+5

3. 2 * 7+5=19

y=19

4 0

3 years ago

Solve the system of equations. 5x−4y=−10 -4x + 5y = 8

777dan777 [17]

Answer:

x= -2 y=0

Step-by-step explanation:

3 0

3 years ago

-35.9=y/0.1+0.1 please help me with this.

Artist 52 [7]

Answer:

358.9 I think

Step-by-step explanation:

6 0

2 years ago

An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so $n = 40$ .

The probability that any integrated circuit is defective is 0.01, so $\pi = 0.01$

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability $P(X > 0)$ , or there are no defective integrated circuits, that is probability $P(X = 0)$ . The sum of these probabilities is decimal 1. We want to find $P(X>0)$ .