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Paul [167]
3 years ago
5

the hypotenuse of an isosceles right triangle is 9 centimeters longer than either of its legs. find the exact length of each sid

e.
Mathematics
2 answers:
Sindrei [870]3 years ago
8 0
The exact value of the side length is 9+9sqrt2 If you use Pythagorean theorem with x as the sides and x+9 as the hypotenuse you will get the correct answer.
Svetradugi [14.3K]3 years ago
5 0
It will be 9cm, 9cm and 18 cm
You might be interested in
A number cube with faces labeled 1 to 6 is rolled once.
Zepler [3.9K]

Answer:

a)  A ∪ B = {2, 4, 5, 6}

b)  A ∩ B = {6}

c)  \sf B^c = {1, 3, 5}

Step-by-step explanation:

Set notation is used in math to list numbers, objects or outcomes.

It uses <u>curly brackets</u> called "braces". Objects placed within the braces are the elements of the set.

The listing method of <u>set notation</u> simply lists the numbers in the set.

The three dots "..." means it is infinite (goes on forever).

Given:

  • A number cube with faces labeled 1 to 6.

Therefore the set of all possible outcomes is {1, 2, 3, 4, 5, 6}.

<u>Event A</u>

The number rolled is <u>greater than 4</u>.

Therefore, the set of outcomes for event A is {5, 6}.

<u>Event B</u>

The number rolled is <u>even</u>.

Therefore, the set of outcomes for event B is {2, 4, 6}.

<u>Part (a)</u>
Event "A or B" means the outcomes in A or B or both.

⇒ A ∪ B = {2, 4, 5, 6}

<u>Part (b)</u>

Event "A and B" means the outcomes in both A and B.

⇒  A ∩ B = {6}

<u>Part (c)</u>

The complement of event B means everything that is not in B.

\sf \implies B^c =<em> </em>{1, 3, 5}

Learn more about set notation here:

brainly.com/question/27913822

4 0
1 year ago
Which equation would you use to find x?
Nitella [24]
You would use B to find X
8 0
3 years ago
Help anyone ? Pls n thank you
Ostrovityanka [42]

Answer:

3^{6} =729

Step-by-step explanation:

3^{6} ÷ 3^{5} = X ÷ 243 =3

So X = 3×243= 729

4 0
3 years ago
Find the fifth roots of 243(cos 260° + i sin 260°).
Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5)  where k=0,1,2,3,4


So the first root of 243 (cos 260° + i sin 260°)  

is z1 =  243^1/5 ( cis ( 260 + 360 *0)/5)  

          3 cis ( 260/5)

        = 3 cis (52)

        = 3 cos (52 + i sin 52)


The second root of  243 (cos 260° + i sin 260°)  

is z2 =  243^1/5 ( cis ( 260 + 360 *1)/5)  

          3 cis ( 620/5)

        = 3 cis (124)

        = 3 cos (124 + i sin 124)


The third root of  243 (cos 260° + i sin 260°)  

is z3 =  243^1/5 ( cis ( 260 + 360 *2)/5)  

          3 cis ( 980/5)

        = 3 cis (196)

        = 3 cos (196 + i sin 196)


The fourth root of  243 (cos 260° + i sin 260°)  

is z4 =  243^1/5 ( cis ( 260 + 360 *3)/5)  

          3 cis ( 1340/5)

        = 3 cis (268)

        = 3 cos (268 + i sin 268)


The fifth root of  243 (cos 260° + i sin 260°)  

is z5 =  243^1/5 ( cis ( 260 + 360 *4)/5)  

          3 cis ( 1700/5)

        = 3 cis (340)

        = 3 cos (340 + i sin 340)

6 0
3 years ago
Find the maximum and minimum values of the function below on the horizontal span from 1 to 5. Be sure to include endpoint maxima
mote1985 [20]

Answer:

Max = 86; min = 36.54

Step-by-step explanation:

f(x) = x^{2} + \dfrac{85}{x}

Step 1. Find the critical points.

(a) Take the derivative of the function.

f'(x) = 2x - \dfrac{85}{x^{2}}

Set it to zero and solve.

\begin{array}{rcl}2x - \dfrac{85}{x^{2}} & = & 0\\\\2x^{3} - 85 & = & 0\\2x^{3} & = & 85\\\\x^{3} & = &\dfrac{85}{2}\\\\x & = & \sqrt [3]{\dfrac{85}{2}}\\\\& \approx & 3.490\\\end{array}\

(b) Calculate ƒ(x) at the critical point.  

f(3.490) = 3.490^{2} + \dfrac{85}{3.490} = 12.18 + 24.36 = 36.54

Step 2. Calculate ƒ(x) at the endpoints of the interval

f(1) = 1^{2} + \dfrac{85}{1} = 1 + 85 = 86\\\\f(5) = 5^{2} + \dfrac{85}{5} = 25 + 17 = 42

Step 3.Identify the maxima and minima.

ƒ(x) achieves its absolute maximum of 86 at x = 1 and its absolute minimum of 36.54 at x = 3.490

The figure below shows the graph of ƒ(x) from x = 1 to x = 5.

5 0
3 years ago
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