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Gennadij [26K]
3 years ago
9

Can you factor x^2+6z+12 please

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0
To solve we have to write 12x as 2x+10x 
<span><span>x2</span>+2x+10x+20</span>
taking x and 10 as a common
x(x+2)+10(x+2)
now (x+2) is common
<span>(x+2)(x+10) answer</span>
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A hamster eats2/7 of a bag of carrots each day. Work out how many days it takes the hamster to eat 8 whole bags of carrots.​
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It will take the hamster 28 days to eat 8 whole bags of carrots.

If you divide 8 by 2/7 you will get the answer of 28.
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jek_recluse [69]
The correct answer is 7. 85
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3 years ago
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During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by
sweet [91]

Hey Child.

The answer to this is 1 or 7:

To find the range for the number of measures played to satisfy our solution, we must solve for x using s = 80.

Next, we subtract 50 from both sides of the equation.

Next, we divide both sides of the equation by 10

Next, to eliminate the absolute value bars, we will add a ± sign in front of our s value, 3.

Finally, we add 4 to both sides of our equation giving us 4 ± 3 = x

Separating this into two equations, we get 4 - 3 = x and 4 + 3 = x

Therefore, x, the number of measures of music played, must be either 1 or 7.

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4 0
4 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ​ ,0)left parenthesis, plus min
lora16 [44]

Answer:

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the  relation between the focus and semi major axes and semi minor axes as:

\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 }  \\ \\ \mathbf{c^2 = 49 } \\ \\  \mathbf{c = \sqrt{49 }}

The equation of ellipse formula is:

\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

and we know that \mathbf{a=\sqrt{49}  \ \  and  \  \ b=\sqrt{37}}

Thus ; the equation of the ellipse at the origin is

\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}

3 0
4 years ago
Round: 816.868906667<br> To the nearest hundredth
zloy xaker [14]

Answer:

The answer is 816.87

3 0
3 years ago
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