We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .
The equation and the point is;

We know that for two lines to be perpendicular, the product of their slopes should be -1.
Therefore, the slope of the perpendicular should be;

The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;

Inserting all values, we have,

That is the final answer.
Answer:
If you want them at the same exact point then since the theif is 9 steps ahead it
will take 3 seconds
Step-by-step explanation:
Robber:
<em>starts at 9</em>
<em>starts at 9add on 5 and you get 14</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>
Police:
<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>
<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>
<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>
<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>
A cylinder with a height of 2 and a diameter of 8. Please mark brainliest.
Compute the necessary values/derivatives of
at
:






Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial)
at
by


###
Another way of doing this would be to solve for the coefficients
in

by expanding the right hand side and matching up terms with the same power of
.