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Alexxx [7]
2 years ago
10

The gas tank of a 2013 Honda Accord holds 17.2 gallons. How many pounds of carbon dioxide are produced by burning an entire tank

of gas?
i don't know how but its a math problem
Mathematics
1 answer:
cricket20 [7]2 years ago
8 0
One gallon of gasoline (6.3 lbs.) produces about 20 lbs. of carbon dioxide. This may seem weird and untrue, however, most of that weight comes from the oxygen in the air. Following the math on this means that we multiply 17.2 gallons of gas by 20 lbs. of co2 per gallon of gas burned. 
This gives us the answer of 344 lbs. of carbon dioxide burned per tank of gas. (From a 2013 Honda Accord)
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4 0
3 years ago
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evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

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Answer:

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