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borishaifa [10]
3 years ago
14

How much would it have rained each month if the total amount rain (11 inches) was redistributed equally among the 12 moths of th

e year?
Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

Total rainfall in one month 0.9167 inches

Step-by-step explanation:

The total rainfall around an year is equal to  11 inches

There are 12 months in an year.

Total rainfall in one month is equal to total rainfall in an year divided by number of months

Total rainfall in one month

\frac{11}{12} = 0.9167 inches

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A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An
Gnom [1K]
I would solve this using tangents.  Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
tan A = \frac{h+70}{40}  , tan B = \frac{70}{40}

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
tan (A-B) = \frac{tanA - tanB}{1+tan A  tan B}
Plug in what we know:
tan(9) = \frac{ \frac{h+70}{40} -  \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}
tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}
h = \frac{650 tan(9)}{4-7 tan(9)}
h = 35.6
7 0
3 years ago
If we sample from a small finite population without replacement, the binomial distribution should not be used because
Nezavi [6.7K]

Using the hypergeometric distribution, it is found that there is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

For this problem, the parameters are given as follows:

N =A + B = 54, k = 4, n = 4.

The probability of getting exactly two winning numbers with one ticket is P(X = 2), hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,54,4,4) = \frac{C_{4,2}C_{50,2}}{C_{54,4}} = 0.0232

There is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

3 0
2 years ago
14V + 5 − 5V = 4(V + 15)
OleMash [197]

Answer:

V=11

Step-by-step explanation:

Simplify:

14V-5V+5=4V+60

9V+5=4V+60

Subtract 4V on both sides:

9V-4V+5=4V-4V+60

Solve:

5V+5=60

Subtract 5 on both sides:

5V+5-5=60-5

5V=55

Divide by 5

V=11

Hope this helps!

8 0
3 years ago
Read 2 more answers
Find the area of the triangle whose vertices are (0,4) , (0,0) and (2,0) by plotting them on graph
Luden [163]

Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.

Anyway, it means that the area is given by

A = \cfrac{\overline{AB}\times\overline{AC}}{2}

Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:

\overline{AB} = |2-0| = |2| = 2

The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:

\overline{AC} = |4-0| = |4| = 4

So, the area is

A = \cfrac{2\times 4}{2} = 4

4 0
3 years ago
Amir can run 15 kilometers in one hour. How many kilometers can Amir run per minute?
inysia [295]
Amir can run 0.25 kilometers per minute.
5 0
4 years ago
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