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Katyanochek1 [597]
3 years ago
10

Which equation is equivalent to..???

Mathematics
2 answers:
JulsSmile [24]3 years ago
7 0

Answer:√(x) +11=15 is equivalent to

√(x) =15-11

Step-by-step explanation:

√(x) +11=15

Subtract 11 from both sides

√(x) +11-11=15-11

√(x) =15-11

maw [93]3 years ago
6 0

Answer:

that is the solution to the question

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Lucy bought three books at a bookstore. Here are their prices (in dollars).
Valentin [98]

Answer:

41.82$

Step-by-step explanation:

The prices are

7.58$, 16$, 18.24$.

To get the total of all what Lucy bought, You add the prices altogether.

That is,

18.24$

+16.00$

+<u>0</u><u>7</u><u>.</u><u>5</u><u>8</u><u>$</u>

41.82$

The total amount of what Lucy bought is 41.82$

8 0
2 years ago
The table shows the distance Allison drove on one day of her vacation. Is the relationship between the distance and the time a p
Anuta_ua [19.1K]

Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h)              1         2        3          4        5

Distance (mi)       55    100     165     280    250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

substitute y = 250, x = 5

k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

6 0
3 years ago
Bro help me plss <br> tippy tap so i get the character limit
Alinara [238K]

Answer:

im n  idiot

Step-by-step explanation:

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3 0
2 years ago
... If g(x)= x^2 + 3x, what is the value of g(-3).<br> (1) 0<br> (3) 18<br> (2)3<br> (4) 21
diamong [38]

Answer:

g(-3) = 0

Step-by-step explanation:

hello :

g(-3) = (-3)² + 3(-3) = 9-9 =0

3 0
2 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
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