Given:
b1 = 17 ft
b2 = 20 ft
h = 13 ft
r = 17/2 = 8.5 ft
Area of the Semi-circle = 1/2 π r²
= 1/2 (22/7) (8.5²)
= (11/7) (72.25)
= 113.535 ft²
Area of the trapezium = (h) (b1 + b2) / 2
= (13)(17 + 20)/2
= 240.5 ft²
Total area of the amphitheater stage = Area of Semi-circle + Area of the trazezium = 113.535 + 240.5 = 354.035 ft²
Answer:
Hey mate, just subsitute all the G's for -7 and all the H's for 3 in the question. Then put the question number in the blank that the answer matches.
Step-by-step explanation:
Answer: 6x
Work Shown:
For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that
meaning that the log base of itself is 1
log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above
log(b^(6x)) = 6x*1 .... use the second rule mentioned
log(b^(6x)) = 6x
Answer:
44.4 is the answer for this problem be sure to mark brainliest if helpful.
Answer:
See below
Step-by-step explanation:


To prove 1 we have

Hence proved
To prove 2

Hence proved
<u>Notes</u>
The complement of a set is the set of all elements <u>not</u> in the set
Here the set of all outcomes is {1, 2, 3,4,5, 6}
So if A = {2, 4, 6} then the complement of A s=is the set of outcomes not in A ie the set {1, 3, 5} which is the set of odd numbers on a die throw
The union of two sets is the set of all elements in both sets without duplication
The intersection of two sets is the set of all elements common to both sets