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Morgarella [4.7K]
3 years ago
15

HELP.......................

Mathematics
1 answer:
ira [324]3 years ago
7 0
1. 1 2. 1 1/43.1 1/4
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Solve for u in the proportion.<br> 40/15 = u/6<br> URGENT
sammy [17]

Answer:

16

Step-by-step explanation:

40x 6 =u x 15

240=u x 15

U = 240÷15

U = 16

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4 years ago
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I really want to finish this homework and I want to say what’s 9+9
larisa86 [58]

Answer:

Step-by-step explanation:

9+9=18

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Ava bought 25 kg of fish-flavored cat food and 35 kg of chicken-flavored cat food for the cat rescue center. He is going to divi
Ivan
Because the type of cat food is irrelevant we can add them together:
25 + 35 = 60 kg of cat food

1 kg = 1,000 grams
60 kg = 60,000 grams

60,000 / 300 gram pockets = 200 pockets
He will make 200 pockets (with 60kg of food)

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3 years ago
Integrate dx/3sinx+4cosx
german

\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}

A standard approach would be the tangent half-angle substitution:

t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx

Then

\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}

\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}

from which we get

\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt

So the integral becomes

\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}

Rewrite the denominator as

2t^2-3t-2=(2t+1)(t-2)

and expand the integrand into its partial fractions:

\dfrac1{2t^2-3t-2}=\dfrac15\left(\dfrac1{t-2}-\dfrac2{2t+1}\right)

We have

\displaystyle-\frac15\int\frac1{t-2}-\frac2{2t+1}\,\mathrm dt=-\frac15(\ln|t-2|-\ln|2t+1|)+C

=\dfrac15\ln\left|\dfrac{2t+1}{t-2}\right|+C

=\dfrac15\ln\left|\dfrac{2\tan\frac x2+1}{\tan\frac x2-2}\right|+C

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3 years ago
Surface Area<br>I need help
klasskru [66]
The surface area of the bottom and top is 60.Two of the sides are 30 two are 18. The total surface area adds up to 216.
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