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Kaylis [27]
1 year ago
15

O 12 Ms. Ruby has 1 beanbag chair in her room. She lets 4 students take equal turns sitting in the chair during a 38-minute read

ing period. How long is each student's turn in the beanbag? * O 1/4 minutes O 4/1 minutes 4/28 minutes O 38/4 minutes
Mathematics
1 answer:
My name is Ann [436]1 year ago
5 0

The number of students allowed to sit, N=4.

The total number of minutes, T=38 minutes.

Let x be the number of minutes for a student

\begin{gathered} 4\text{ students-}\longrightarrow38\text{ minutes} \\ 1\text{ student--x} \\ \text{Cross multiplying,} \\ x=\frac{38\text{ minutes}}{4\text{ students}}\times1\text{ students} \\ =\frac{38}{4\text{ }}\text{minutes} \end{gathered}

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Answer:

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The height after four seconds is h(4) = -16 * r² + 144*4+160 = 480

The maximum height of the ball is the value it takes at its vertex 'v = -b/2a'. In this case a = -16 and b = 144, so the v = -144/-32 = 4.5. The maximum height of the ball as a result is h(4.5) = -16 (4.5)² + 144*4.5 + 160 = 484

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Since t cant take negative values, then the correct value is 10. The ball hits the ground after 10 seconds.

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