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photoshop1234 [79]
4 years ago
12

If we expect to get a number less than 3 in eighty times spinning an eight-part spinner numbered 1 to 8, how many times would we

have spun?
60
120
240
320
Mathematics
1 answer:
mestny [16]4 years ago
4 0
You have eight numbers in total. Only two (1 and 2 are less than 3. You do not include 3) of them will bring success.
Let x = the total number of times you need to spin.

(2/8)x = 80 Multiply by 8
2x = 80 * 8
2x = 640 Divide by 2
x = 640 / 2
x = 320

D <<<< answer. 
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