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defon
3 years ago
13

What is the GCF of 15 and 30

Mathematics
2 answers:
anygoal [31]3 years ago
6 0
The greatest common factor (GCF) of 15 and 30 is: 15

Factors of 15: 1, 3, 5, 15
Factors of 30: 1, 2, 3, 5, 6, 10, 15

The common factors between the two numbers are 1, 3, 5, and 15, but considering 15 is the highest number out of them all, it is the greatest common factor. 
BaLLatris [955]3 years ago
5 0
The greatest common factor is 15
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What is the sum of 6 feet 10 inches and 8 feet 9 inches
slega [8]


6 ft 10 in + 8 ft 9 in = 15 ft 7 in

add the inches first and then subtract 12 from the 19 because 12 inches  equals 1 foot then  add 6+8+1=15 ft  don't forget to include the 7 inches in your answer

4 0
2 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.
Katyanochek1 [597]

The value of x would have to be 90 degrees as it is a right angle.


Thank you,

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3 0
3 years ago
Read 2 more answers
What is the remainder when the product of the 5 smallest prime numbers is divided by 42?
sveta [45]

Answer:

0

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

5 0
3 years ago
Modulation is the process of a)Spinning a wheel to generate a sine wave b)Increasing the amplitude of a sine wave c)Changing one
hram777 [196]

Answer: C) Changing one or more properties of a sine wave in response to data.

Step-by-step explanation:

Modulation is primarily used in telecommunications sector. It the process by which data is transmitted via electrical signals. It is the process of imposing an input signal on to a wave carrier. It is the pillar of data communication that enables the use information carriers of signals that are electrical and optical. Altering the carrier/ periodic waveform results in Modulation. The amplitude frequency and phase are conveyed. There are different types of Modulation which includes: amplitude Modulation, frequency Modulation, and phase Modulation.

5 0
3 years ago
A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec
VMariaS [17]

Answer:

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=19.1 represent the sample mean

\mu population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that t_{\alpha/2}=

Now we have everything in order to replace into formula (1):

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

5 0
3 years ago
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