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AveGali [126]
2 years ago
15

5x-6=3x what does x equal

Mathematics
2 answers:
baherus [9]2 years ago
6 0
5x-6= 3x
⇒ 5x-3x= 6
⇒ 2x= 6
⇒ x= 6/2
<span>⇒ x= 3</span>
makvit [3.9K]2 years ago
3 0
5x-6= 3x
⇒ 5x-3x= 6
⇒ 2x= 6
⇒ x= 6/2
⇒ x= 3

Final answer: x=3~
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Three years ago a school spent four hundred thirty-eight thousand, seven hundred sixty-nine dollars and seventy-nine cents build
alukav5142 [94]
Answer: $438,769.79
Please mark me Brainliest
4 0
2 years ago
If Benito is selecting samples of five values from the table, which row will result in the greatest mean? Population Data Row 1
Vilka [71]

Answer:

4th row will result in the greatest mean.

Step-by-step explanation:

We are asked to find the row with greatest mean from our given rows.

We will use formula \bar{x}=\frac{\Sigma x}{n}, where,

\bar{x}=\text{Mean},

\Sigma x=\text{Sum of all data values},

n=\text{Number of data points in sample}

Let us find mean of each row using above formula.

\text{Mean of row 1}=\frac{4+2+2+3+3}{5}

\text{Mean of row 1}=\frac{14}{5}

\text{Mean of row 1}=2.8

Therefore, mean of 1st row is 2.8.

\text{Mean of row 2}=\frac{3+3+4+3+2}{5}

\text{Mean of row 2}=\frac{15}{5}

\text{Mean of row 2}=3

Therefore, mean of 2nd row is 3.

\text{Mean of row 3}=\frac{2+4+3+4+3}{5}

\text{Mean of row 3}=\frac{16}{5}

\text{Mean of row 3}=3.2

Therefore, mean of 3rd row is 3.2.

\text{Mean of row 4}=\frac{3+4+4+7+3}{5}

\text{Mean of row 4}=\frac{21}{5}

\text{Mean of row 4}=4.2

Therefore, mean of 4th row is 4.2.

Since 4th row has the highest mean, therefore, 4th row will result in the greatest mean.

6 0
2 years ago
Read 2 more answers
A. 155<br> B. 163 1/2<br> C. 123<br> D. 122<br> E. 122 1/2<br> F. 130
Lesechka [4]
I think D but don’t take my word for it
5 0
3 years ago
Read 2 more answers
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
The sum of two consecutive integers is -133 find the integers
Bess [88]
-133/2=-66.5

If we take the upper and lower round of that number we will get the 2 consecutive numbers that make -133.
Therefore the answer is -66 & -67.
8 0
3 years ago
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