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Scrat [10]
3 years ago
14

Find the sum of -3/2 - 7/4 + 1/8

Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

The sum of -3/2-7/4+1.8 = -3.125

Ymorist [56]3 years ago
4 0

Answer: -25/8

Step-by-step explanation:

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If 3(d+1)=4(d–2)<br> then what is the value of 5(d–2)
Sonja [21]

Answer:

5(d - 2) = 45

Step-by-step explanation:

Solve the given equation for d

3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides

3d + 3 = 4d - 8 ( subtract 3d from both sides )

3 = d - 8 ( add 8 to both sides )

11 = d

Then

5(d - 2) = 5(11 - 2) = 5(9) = 45

3 0
3 years ago
The top of a mountain is 2,450 feet above sea level a shipwreck was discover 310 feet below sea level what is the distance betwe
arlik [135]

Answer:

d=2,760\ ft

Step-by-step explanation:

Let

x ----> the height of the top of a mountain above sea level

y ----> the deep of a shipwreck below the sea level

we know that

The sea level represent the height equal to zero

In this problem we have

x=2,450\ ft ---> is positive because is above sea level

y=-310\ ft ---> is negative because is below sea level

To find out the distance between the mountain top and the ship wreck, determine the absolute value of the difference between the two values

d=\left|x-y\right|

substitute the values

d=\left|2,450-(-310)\right|

d=\left|2,450+310\right|

d=\left|2,760\right|

d=2,760\ ft

5 0
3 years ago
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
Read 2 more answers
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
How many minutes are there in 4 and a half hours?
Annette [7]
1 \ hour=60 \ minutes \\\\ a \ half \ an \ hour = \frac{1 \ hour}{2}=\frac{60min}{2}=30 minutes \\\\ 4 \ hurs \ and \ a half = 4*60+30= \\\\ =240+30=\\\\ =\boxed{270}
7 0
3 years ago
Read 2 more answers
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