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Scrat [10]
3 years ago
14

Find the sum of -3/2 - 7/4 + 1/8

Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

The sum of -3/2-7/4+1.8 = -3.125

Ymorist [56]3 years ago
4 0

Answer: -25/8

Step-by-step explanation:

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Please help I’ll give you brainlist or something
harkovskaia [24]

Answer:

1 slope of f is 5

slop of g is 2

2. connor

initial value is 200

rate of change is -10

Pilar

initial value is 242

rate of change is -8

3.

y intercept of f is -3

y intercept of g is -1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find an equation parallel to the line, y= -3x -1
Aleks04 [339]

Answer:

y = 3x -2

Step-by-step explanation:

If the line is parallel, that means it has the same slope. The given equation had a slope of 3, so the new line must also have a slope of 3.

You can plug the given coordinates into the slope-intercept form with a slope of 3 to find your answer.

y = m*x + b

7 = 3*3 + b

7 = 9 + b

-2 = b

y = 3x -2

I Hope This Helps :D

7 0
3 years ago
Read 2 more answers
Four different positive integers have a product of 110.<br>What is the sum of the four integers?​
BigorU [14]
<h3>Answer:  19</h3>

Explanation:

Let's break 110 down into its prime factors

110 = 11*10

110 = 11*2*5

110 = 2*5*11

We have three different prime factors that multiply to 110. However, the instructions say there are 4 integers that multiply to 110. To fix this, we can say

110 = 1*2*5*11

now we see that 1,2,5 and 11 multiply out to 110

They add to 1+2+5+11 = 3+16 = 19

3 0
3 years ago
-3.667987=b^(-2)w+(-1.981902-w)
xxTIMURxx [149]

Answer:

what are the answers?

Step-by-step explanation:

7 0
3 years ago
The distribution of scores on the SAT is approximately normal with a mean of mu = 500 and a standard deviation of sigma = 100. F
ella [17]

Answer:

a. 2.28%

b. 30.85%

c. 628.16

d. 474.67

Step-by-step explanation:

For a given value x, the related z-score is computed as z = (x-500)/100.

a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)

b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)

c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently  P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552

d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653

4 0
3 years ago
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