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3 years ago

What is the sum of 6 7/8+4 5/8 =?

Mathematics

2 answers:

Lerok [7]3 years ago

7 0

Answer 11 1/2 hope this help if you ever need anything else contact me<3

lianna [129]3 years ago

4 0

The answer is 11 1/2
Hoped that helped

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A=b-2<br>a+b=a×b<br>Prove that a and b aren't whole numbers

Brut [27]

\left[a \right] = \left[ \frac{2\,b}{3}\right][a]=[32b] totally answer

7 0

4 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

Find the least common denominator for these

baherus [9]

Answer:

The least common denominator of the two rational expressions is $(x+2)^{2}\cdot (x+3)$ .

Step-by-step explanation:

Let be the following rational expressions:

$\frac{x^{3}}{x^{2}+4\cdot x + 4}, \frac{-9}{x^{2}+5\cdot x + 6}$

Then, we factor each denominator:

$\frac{x^{3}}{(x+2)^{2}}, \frac{-9}{(x+3)\cdot (x+2)}$

Now, we compare each denominator to find all missing binomials so that each expression may have a common denominator:

$\frac{x^{3}}{(x+2)^{2}} \rightarrow (x+3)$

$\frac{-9}{(x+3)\cdot (x+2)} \rightarrow (x+2)$

Hence, we conclude that least common denominator of the two rational expressions is $(x+2)^{2}\cdot (x+3)$ .

8 0

3 years ago

Cuánto es 729 entre 38

riadik2000 [5.3K]

Answer: 19.1842

Step-by-step explanation:

8 0

3 years ago

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar

Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0

3 years ago