<u>Answer:</u>
The range of the function y = 2cos x is -2 <y < 2 .
<u>Step-by-step explanation:</u>
We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,
since ,
cos (x + 2π) = cos x
So, the range of the function y = 2cos x is -2 <y < 2 .
Answer:
Domain: {-2, -3, 6, 8, 10}
Range: {-5, 1, 7, 9}
Step-by-step explanation:
Given:
{(6, -5), (-2, 9), (-3, 1), (10, 7), (8, 9)}
✔️Domain:
This includes all the set of the x-values that are in the relation. This includes, 6, -2, -3, 10, and 8.
Thus, the domain can be represented as:
{-2, -3, 6, 8, 10}
✔️Range:
This includes all corresponding y-values in the relation. They are, -5, 1, 7, and 9.
Range can be represented as:
{-5, 1, 7, 9}
As we can notice the shape is a Pentagon. A Pentagon's angles should add up to 540. So we can use simple addition and subtraction to solve.
121 + 108 + 102 + 100 = 431
540 - 431 = 109
109 should be your answer
To solve for n, we have to isolate n. To do so, we move all the terms that are not n to one side of the equation, and leave n on the other side.
Equation: n + 5/16 = -1
Subtract 5/16 on both sides to bring it to the right side of the equation.
Correct answer:
First reflect across the y-axis, then rotate 90 degrees clockwise about point K, then shift 3 units down.
