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3 years ago

At what point will 3y=4x-6 and 8x-6y=-30 intercept

Mathematics

1 answer:

tester [92]3 years ago

3 0

Answer:

The lines don't intercept

Step-by-step explanation:

we have

$3y=4x-6$

isolate the variable y

Divide by 3 both sides

$y=\frac{4}{3}x-\frac{6}{3}$

simplify

$y=\frac{4}{3}x-2$ -----> equation A

$8x-6y=-30$

Isolate the variable y

$6y=8x+30$

Divide by 6 both sides

$y=\frac{8}{6}x-\frac{30}{6}$

simplify

$y=\frac{4}{3}x-5$ -----> equation B

Compare equation A and equation B

The slopes are the same and the y-intercepts are different

Remember that

If two lines has the same slope, then the lines are parallel

therefore

In this problem line A and line B are parallel lines

The system of equations has no solution, because the lines don't intercept

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What is the image of (-9,0) after a reflection over the line y=x

SpyIntel [72]

Answer:

(0,-9)

Step-by-step explanation:

The image of a point $(x,y)$ over a line $y=x$ is given by the co-ordinate rule:

$(x,y)$ → $(y,x)$

So, when we reflect a point over the line $y=x$ , the x co-ordinate and y co-ordinate change their places.

Here, $(x,y)$ is $(-9,0)$ . So, from the above rule, after reflection over the line $y=x$ , the image has the following co-ordinates:

$(0,-9)$

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3 years ago

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erastovalidia [21]

Answer:

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3 years ago

Find the surface area of the following figure.

fgiga [73]

Answer:

$\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.$

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

$\qquad\boxed{\sf Area_{(square)}= side^2}$

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}$

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

$\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x \\\\\sf\implies x = \dfrac{ b}{3}$

$\rule{200}2$

Hence the TSA of cuboid in terms of lenght and breadth is :-

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}$