We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2
This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A
Whats the problem? i cant solve it w/o the problem doll
Answer:
Step-by-step explanation:
This question is illustrated using the attachment and will be solved using cosine formula
<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>
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The cosine formula in this case is:
Where
The equation becomes
Collect Like Terms
Using quadratic formula:
Where
or 
or 
or 
But length can not be negative.
So:
The piece Zoe cut off would be 1 and 5/12 ft long.
5 and 1/4 - 3 and 5/6
The least common denominator is 24.
5 and 6/24 - 3 and 20/24
5 and 6/24 becomes 4 and 30/24
4 and 30/24 - 3 and 20/24 = 1 and 10/24
1 and 10/24 can be simplified to 1 and 5/12.
