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UkoKoshka [18]
3 years ago
8

If each angle in a decagon is the same measure, what is that measure? 18° 180° 144° 72°

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

Each Angle of Decagon = 144 degrees

Step-by-step explanation:

The interior angles of a decagon add up to 1440

If they are of the same measure, then every angle will be equal to:

Each Angle of Decagon = 1440/10

Each Angle of Decagon = 144 degrees

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andrew-mc [135]
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Solve each prportion. (2/y-4)=(y+3/4)
vampirchik [111]

Answer:

y = 5, -4

Step-by-step explanation:

To solve proportions you cross-multiply.

\frac{2}{y-4} =\frac{y+3}{4} \rightarrow 2\times4 = (y-4)\times(y+3) \rightarrow 8=y^2-y-12

Now that we have 8 = y^2 - y - 12, we must make the entire trinomial equal to 0 by subtracting 8 from both sides.

y^2 - y - 20 = 0

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Make both factors equal to 0 to solve for both values of y.

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y = 5, -4

4 0
3 years ago
Emily lived in a blue house for 4.5 years. Then she lived in a yellow house for 3.6 years. How many years did Emily live in the
ikadub [295]
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You invested $19,000 in two accounts paying 4% and 8% annual interest, respectively.
saveliy_v [14]

Answer:

$9000 at 4$

and

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Step-by-step explanation:

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Recall the formula for interest as : I= P * R *t

where I is the interest, R is the annual rate of interest and t is the number of years.

Since there are two investments, we need to add both interests at the end of the one year: I1 = x (0.04) (1) = 0.04 x   and   I2 = y (0.08) (1) = 0.08 y

Total Interest = Interest (from the 4% account) + Interest (from the 8% account)

Total Interest = $1160 = 0.04 x +  0.08 y

we also know that the total invested (x + y) adds to $19,000, that is:

$19,000 = x + y

Then we can solve these system of two equations by substitution, for example solving for y in the second equation and using the y substitution in the first equation;

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1160 = 0.04 x + 1520 - 0.08 x

0.08 x - 0.04 x = 1520 - 1160

0.04 x = 360

x = 360/0.04 = $9000

Then the other investment was : y = $19000 - $9000 = $10000

6 0
3 years ago
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