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2 years ago

Which of the equations below could be the equation of this parabola?

Mathematics

1 answer:

Evgen [1.6K]2 years ago

4 0

Answer:

Step-by-step explanation:

The parabola opens to the right

therefor it will be of the form x = +y^2

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How do i solve for x if 6x - 6 - 7x =6

Dmitry_Shevchenko [17]

Answer:

X = 12

Step-by-step explanation:

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

-x - 12 = -1 • (x + 12)

Equation at the end of step 1 :

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : -x-12 = 0

Add 12 to both sides of the equation :

-x = 12

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2 years ago

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Which points on the number line represent the quotients of these expressions? 12 divided by -6 and -15 divided by -3

yaroslaw [1]

Answer:

2,5

Step-by-step explanation:

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2 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Anastasy [175]

Answer:

$\frac{(a-b)^2+b^2}{a^2}$

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

$=\sqrt{(a-b-0)^2+(0-b)^2}$

$=\sqrt{(a-b)^2+b^2}$

Thus the area of the inner square = (side)²

$=(\sqrt{(a-b)^2+b^2})^2$

$=(a-b)^2+b^2\text{ square cm}$

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

$=\sqrt{(a-0)^2+0^2}$

$=\sqrt{a^2}=a$

Thus, the area of the outer square = (side)²

$=a^2\text{ square cm}$

Hence, the ratio of the area of the inner square to the area of the outer square

$=\frac{(a-b)^2+b^2}{a^2}$

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2 years ago

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Recycling paper is the best way to protect trees. Recycling prevents trees from being cut down and used for paper and other prod

zubka84 [21]

Answer:

Recycling saves trees

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2 years ago

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Which equation represents a proportional relationship? A. y = x + 1 3 y=x+13 B. y = 1 − 1 3 x y=1-13x C. y = 3 x + 1 3 y=3x+13 D

34kurt

Answer:

Option D. $y=\frac{1}{3}x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

<u><em>Verify each case</em></u>

case A) we have

$y=x+\frac{1}{3}$

Remember that

the line must pass through the origin

For x=0, y=0

In this case

For x=0

$y=0+\frac{1}{3}=\frac{1}{3}$

The line not passes through the origin

therefore

The equation A not represent a proportional relationship

case B) we have

$y=1-\frac{1}{3}x$

Remember that

the line must pass through the origin

For x=0, y=0

In this case

For x=0

$y=1-\frac{1}{3}(0)=1$

The line not passes through the origin

therefore

The equation B not represent a proportional relationship

case C) we have

$y=3x+\frac{1}{3}$

Remember that

the line must pass through the origin

For x=0, y=0

In this case

For x=0

$y=3(0)+\frac{1}{3}=\frac{1}{3}$

The line not passes through the origin

therefore

The equation C not represent a proportional relationship

case D) we have

$y=\frac{1}{3}x$

Remember that

the line must pass through the origin

For x=0, y=0

In this case

For x=0

$y=\frac{1}{3}(0)=0$

The line passes through the origin

therefore

The equation D represent a proportional relationship

3 0

2 years ago