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inn [45]
3 years ago
11

the daytime speed limit on interstate and state highways in texas is 70 miles per hour. at night, the maximum speed is 65 miles

per hour.in what way would the graph showing the distance traveled at night differ from the one showing daytime travel? a)the slope would decrease b)the slope would increase c) the y-intercept would decrease d) the x-intercept would increase
Mathematics
1 answer:
exis [7]3 years ago
4 0
I think it's c) the y-intercept would decrease
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16.375 or 16 3/8

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3 years ago
Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair
umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

<u>Maximum value occurs at 325 at the point (0, 325)</u>

<u>Step-by-step explanation:</u>

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0
3 years ago
Write an expression in simplest form that represents the cost for shampooing and cutting w women's hair and m men's hair.
tensa zangetsu [6.8K]

Answer:

the cost of the women's haircut is $15 and to shampoo the woman's hair is $5

and the cost of the mens hair cut is $7  and to shampoo the mens hair is $2

15+5=$20 is how much it cost for the women.

7+2=$9 is how much it cost for the men.

Step-by-step explanation:

6 0
3 years ago
The quadratic function h(t) = -16.1? + 150 models a ball's height, in feet, over time, in seconds,
Sliva [168]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t) = -16.1t^2 + 150

0=-16.1t^2+150

16.1t^2=150

t^2=\frac{150}{16.1} =9.32

t=+-\sqrt{9.32} =+-3.05

t1=3.05

t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1

b=0

c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

5 0
2 years ago
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