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Grace [21]
3 years ago
8

The 7th grade has 195 students. There are 25 more girls than boys in the grade. How many boys are there in 7th grade

Mathematics
1 answer:
Anon25 [30]3 years ago
5 0
110 girls and 85 boys.

Subtract 1 from 195. Then divide by 2. 194/2 = 97. Then add 13 97+13=110. There are 110 girls.
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The image below shows two parallel lines cut by a transversal. What is the measure of angle 1?
Yuri [45]

180 - 78 = 102

< 1 = 102*

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Help with these questions Please :(
attashe74 [19]
The angle of YWZ is equal to the angle of YWX, and angle WYX is also a right angle due to the congruency of segments WZ and WX.

Every triangle has an angle total of 180 degrees, so angle WXY is equal to

180 - (WYX + YWX)
180 - (90 + 17)
73

Angle WXY has an angle value of 73 degrees.
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I drove 380 miles using 14 gallons of gas. At this rate, how many gallons of gas would I need to drive 418 miles?
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15.4 gallons .

Step-by-step explanation:

The rate of gas used  = 380/14 = 27.14 gallons per gallon.

So for each gallon used  you drive 27.14 miles.

So number of gallons used when travelling 418 miles = 418/27.14

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3 years ago
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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

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                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

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Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

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THey tried to push but the wall doesn't move. So Nobody did any work. Everybody's work done is 0.
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