Can someone help me plz

Which transformations will produce similar, but not congruent, figures?

liubo4ka [24]

The correct answer is <span>A. Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ.
</span>
Congruent figures are of the same shape and the same size. <span>Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ will produce similar but not congruent figures because they have different sizes.</span>

6 0

3 years ago

Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25

Nina [5.8K]

Using the asymptote concept, it is found that:

The vertical asymptote is of x = 25.

The horizontal asymptote is of y = 5.

Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{5x}{x - 25}$

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5$

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

#SPJ1

6 0

2 years ago

A structure covering a sports practice field has the shape of half of a cylinder, as shown. What is the total surface area of th

hoa [83]

wait i dont know why it wont let me comment or see comments but wheres the picture?

3 0

2 years ago

You have a 4 in. X 6in. family picture that you want to resize. You can choose from a 16 in. X 20 in. or an 18 in. X 24 in. Whic

yarga [219]

Answer:

16 in × 20 in

Step-by-step explanation:

Finding the % of the picture that can fit in 16×20 frame

Area of picture= length by width

=4*6=24 in²

Area of frame=Length by width

=16*20=320 in²

% of the picture in the frame will be

(24/320) * 100% =7.5%

2. Finding the % of the picture that can fit in 18 × 24 frame

Area of picture=24 in²

Area of frame =Length by width

=18*24=432 in²

% of the picture in the frame will be;

(24/432)*100%=5.6%

The frame 16 by 20 in will keep 7.5% of the original picture

The frame 18 by 24 in will keep 5.6% of the original picture

Hence you should use the frame of 16 by 20 in because it will keep more of the original picture.

6 0

3 years ago

Reflect AQ'R'S' if Q'(1, -3), R'(-2,-6),<br> and S'(-1,-1) over the x-axis.

castortr0y [4]

Answer:

Step-by-step explanation:

The rule of reflecting over the x-axis is that point (x, y) →( x, -y) so

Q'(1, -3), R'(-2,-6),and S'(-1,-1) reflected over the x-axis, become

Q"(1, 3), R"(-2, 6), and S"(-1, 1) .

6 0

2 years ago