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Blizzard [7]
3 years ago
13

David charges $15 plus $5.50 per hour to mow lawns. Ari charges $12 plus $6.25 per hour to mow lawns. In what situations is aris

charge greater than it equal to David’s charge
Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
Ari's charge is less than David's charge bc David is charging 20. 50 and aris is charging 18. 25
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PLEASE HELP (100 POINTS)
Artyom0805 [142]

\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5

Compare to standard equation of SHM

\\ \rm\Rrightarrow y=Acos(\omega x+\phi)

Here

  • Amplitude=A=-5

\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}

\\ \rm\Rrightarrow \omega=1/2

Well the above one are for extra knowledge .

Solution:-

\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5

\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1

\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)

\\ \rm\Rrightarrow \dfrac{x}{2}=\pi

\\ \rm\Rrightarrow x=2\pi

So.

\\ \rm\Rrightarrow x=2\pi+2\pi n

3 0
2 years ago
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Can someone please help me
azamat

Given:

angle ECB=51 degrees

=>

angle EOB = 2*angle ECB = 2*51 = 102 degrees = arc EAB


Also given minor arc AB = 72 degrees

therefore

minor arc EA = 102-72=30 degrees

5 0
3 years ago
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Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}

This is derived from:
y = ax^2 + bx + c

So, by using the 'sum and product' rule:

a × c = 3 × (-6) = -18

b = -3

Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':

The two numbers are: -6 and 3

Proof:

-6 × 3 = -18 {product}

-6 + 3 = -3 {sum}

Now, since a > 1, we divide a from the results

-6/a = -6/3 = -2

3/a = 3/3 = 1

We then implement these numbers into our equation:

(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}

To find x, we make x the subject of 0:

x - 2 = 0

OR

x + 1 = 0

Therefore:

x = 2

OR

x = -1

So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.


We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
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3 years ago
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I need help! Please show all the steps and work! :)
SashulF [63]
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Classify this triangle by its sides.
bixtya [17]

Answer:

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three sides have different lengths

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