Ask question

Ask question

All categories

2 years ago

13

David charges $15 plus $5.50 per hour to mow lawns. Ari charges $12 plus $6.25 per hour to mow lawns. In what situations is aris

charge greater than it equal to David’s charge

1 answer:

KengaRu [80]2 years ago

7 0

Ari's charge is less than David's charge bc David is charging 20. 50 and aris is charging 18. 25

You might be interested in

Solve the following equation: 3x^3+5x^2-4x-4=0

Rama09 [41]

Answer:

1

Step-by-step explanation:

Simplifying

3x + 2(4x + -4) = 3

Reorder the terms:

3x + 2(-4 + 4x) = 3

3x + (-4 * 2 + 4x * 2) = 3

3x + (-8 + 8x) = 3

Reorder the terms:

-8 + 3x + 8x = 3

Combine like terms: 3x + 8x = 11x

-8 + 11x = 3

Solving

-8 + 11x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 11x = 3 + 8

Combine like terms: -8 + 8 = 0

0 + 11x = 3 + 8

11x = 3 + 8

Combine like terms: 3 + 8 = 11

11x = 11

Divide each side by '11'.

x = 1

Simplifying

x = 1

5 0

2 years ago

Baba Clothing store is a having a 5% off sale on all of its clothing. Which expression represents the discounted price if p is t

Irina18 [472]

Answer:

The total of the prices of all of the baby shirts and sweaters that the store sold during the sale was $420.00. It's possible that 12 sweaters and 8 shirts are sold a bargen

Step-by-step explanation:

4 0

1 year ago

Select the correct answer from the drop-down menu.<br><br> Shapes I and II are

dexar [7]

Answer:

similar but not congruent

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

If

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

2 years ago

Identify the 4 basic transformation

Pavlova-9 [17]

Answer:

Rotation, Reflection, dilation, and translation

Step-by-step explanation:

Rotation: Just rotating the shape; spinning the shape around a point

Reflection: Your shape is either reflecting on the x axis or y axis meaning it is either side by side (y) or up and down (x)

Dilation: Your shape is either going to shrink or get bigger

Translation: Shifting all the points of the figure

8 0

2 years ago