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3 years ago

4x-1=2x+11 what is the value of x and what are the steps?

Mathematics

2 answers:

uranmaximum [27]3 years ago

6 0

Answer:

x=6

Step-by-step explanation:

4x-1=2x+11

4x-2x-1=11

2x-1=11

2x=11+1

2x=12

x=12/2

x=6

adelina 88 [10]3 years ago

3 0

X = 6

You need to isolate the variable or get x on one side of the = sign and a number on the other side.

1. Do the inverse operation and add one to each side of the equation. -1+1= 0 and 11+1=12

2. Subtract 2x from both sides. 2x-2x=0 and 4x-2x=2x.

So we are left with 2x=12 or 2 times some number “x” is equal to twelve.

3. Next we divide both sides by 2
2/2=1 and 12/2=6

So x=6

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3 years ago

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3 years ago

Plz help!

GuDViN [60]

Answer:

5x - y = 27

Step-by-step explanation:

Slope is the direction of line and it is calculated as,

$Slope = \frac{y-y_{1}}{x-x_{1}}
$

where (x₁, y₁) is any two points on the line.

Here, we have given that

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∴ $5 = \frac{y-(-2)}{x-5}
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Hence, the equation of a line is: 5x - y = 27

5 0

3 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$