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sasho [114]
2 years ago
8

Please help it’s just one question <3

Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
7 0
180° :))))))))))))))))))))))
Maru [420]2 years ago
4 0

Answer:

c-270

Step-by-step explanation:

To rotate counterclockwise on a coordinate graph, 90 degrees would put you in quadrant I, so you continue 90 degree rotations until you get to quadrant III.

Hope this helps :)

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Can someone help me with at least one problem and tell me how you got the answer
Vesna [10]
S=16t^2
if t=3 
So you would plug it in
16(3)^2 
Then you multipy 
16*3^2
=144
It is easier if you use a calculator just type in ti 30 calculator online that should help

4 0
3 years ago
PLEASE HELP ME FIGURE OUT WHICH ONE I GOT WRONG, TYSMM :)
otez555 [7]

Answer:

da one in the middle and i do relize this is a test becuse i just took it.

Step-by-step explanation:

6 0
2 years ago
This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.
Ugo [173]

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

A_{rectangle}=10\cdot 6=\underline{60} \\A_{halfcircle}=\frac{3.14\cdot3^2}{2}=\underline{14.13} \\A_{total}=A_{rectangle}+A_{halfcircle} =60+14.13=\boxed{74.13\approx74}

The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

3 0
2 years ago
Read 2 more answers
Who is from india and speaks malyalam i do but i was born in america
natali 33 [55]

Answer:

i don't sorry thanks for the points though

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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