Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 -  3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
             = Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes 
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200  Ways
 
        
             
        
        
        
Answer:
 just look it up on the internet and it will have brainly and you click on the one that says brainly an you will have the answer 
 
        
             
        
        
        
Two numbers that add together to get 0 are called additive inverses of each other.