Answer:
sum of the interior angles x and y gives the exterior angle z
(4n-18)°+(n+8)°=(133-6n)°
4n°-18°+n°+8°=133°-6n°
4n°+n°-18°+8°=133°-6n°
5n°-10°=133°-6n°
5n°+6n°=133°+10°
11n°=143°
11°n/11°=143°/11°
n=13
exterior angle=133-6×13
=133-78
=55
Answer:
IDK I JUST NEED THE POINTS
Step-by-step explanation:
SORRYY :)
Answer:
<u>312π square inches</u>
Step-by-step explanation:
The surface area of a cylinder is the area of <u>both its bases and its lateral area added together. </u>
The area of a circle is <u>pi times the radius squared.</u> The radius in this case would be 6, half of the 12 inch diameter. 6 squared is 36, making one base 36π inches squared. Multiply that by two to get the area of both bases; 73π inches squared.
The lateral area of a cylinder is the <u>circumference of the base multiplied by the height of the cylinder. </u>Circumference being <u>pi times the diameter,</u> it would be equal to 12π. Multiply that by the height to get 240π.
Then <u>add the two values together</u> to get 312π, the final answer.
I'm pretty sure its a^2+b^2=C^2
