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marysya [2.9K]
3 years ago
10

The figure shows a carpeted room. How many square feet of the room are carpeted?

Mathematics
2 answers:
umka2103 [35]3 years ago
5 0

Answer:

Option B. 44 square feet.

Step-by-step explanation:

The figure shows a carted room. We have to find the area of the room which is carpeted.

The given room consist of two rectangles.

Larger rectangle with the sides = 8x (7 - 4 ) feet = 8 × 3 feet and smaller rectangle with the sides = 5 × 4 feet

Area of larger rectangle = 8 × 3 = 24 feet²

Area of smaller rectangle = 5 × 4 = 20 feet²

Total area of the room = 24 + 20 = 44 feet²

Option B. 44 square feet is the answer.

Morgarella [4.7K]3 years ago
3 0
4*5=20

8*(7-4)=24
20+24=44

The trick is to make the figure into two
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Answer:

A≈376.99yd²

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h = 7yd

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3 years ago
What is the slope of the line through (-9,6) and (-3, 9)?
Artyom0805 [142]
To find slope, y2-y1/x2-x1
9-6/-3-(-9)=
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3 years ago
Explanation on How to answer what is the density of an object that has a mass of 73,430 and the volume of 7 m3
scZoUnD [109]

Answer:

Density = 10,490 g/m³

Step-by-step explanation:

Density = mass ÷ volume

here mass = 73,430 g

        volume = 7 m³

density = 73,430 ÷ 7

             = 10490 g/m³

Density = 10,490 g/m³

7 0
3 years ago
Solve the system of equations. y = -6x + 9 y = -3x + 3
abruzzese [7]

- 6x + 9 =  - 3x + 3 \\ 3x = 6 \\ x = 2

Substitute x = 2 into y = - 6x + 9
y =  - 6(2) + 9  \\ y =  - 12 + 9 \\ y =  - 3

Answer : x = 2, y = - 3

Hope this helps. - M
6 0
4 years ago
Read 2 more answers
What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...
navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is 2n^{2} +5n-3.

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  an^{2}+bn+c

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  \dfrac{4}{2} = 2

SO, the first term of the nth term rule equation is an^{2} = 2n^{2}.

Now, in the term 2n^{2}, put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then 2n^{2} = 2 \times (1)^{2} = 2

If n = 2, then 2n^{2} = 2 \times (2)^{2} = 8

If n = 3, then 2n^{2} = 2 \times (3)^{2} = 18

If n = 4, then 2n^{2} = 2 \times (4)^{2} = 32

If n = 5, then 2n^{2} = 2 \times (5)^{2} = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is 2n^{2} +5n-3.

7 0
3 years ago
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