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victus00 [196]
3 years ago
10

What does it mean to find the discriminant of an equation such as x+18 = -x^2

Mathematics
1 answer:
o-na [289]3 years ago
5 0
  • Calculation of the discriminant of the polynomial : 18+x+x²
  1. Applying the formula to calculate the discriminant Δ=b²−4 ⋅ a ⋅ c with :     a = 1, b= 1, c = 18
  2. Δ = (1)² − 4 ⋅ (1) ⋅ (18) = 1 −72 = −71  
  3. The discriminant of the polynomial 18+x+x² is equal to −71

Hope this helped!

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Vincent ran 24 laps on monday. This is 63 2/3 of the maximum number of laps he has run in one day. What is the maximum number of
ivann1987 [24]

63.66%x=24

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4 0
2 years ago
An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
________________________________________
  A = L * w ;  we want to find the dimensions; that is, the values for
                         "Length (L)"  and "width (w)" ; 
_______________________________________
Plug in our given values:
_______________________________________
 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
                   →   (4 L²) / 4 = 9/4 ;
______________________________________
           to get:  →  L² = 9/4 ; 
 Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________          
 
     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

    →  L = 3/2 ; 

    → w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi.  =  (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
___________________________________________________
7 0
2 years ago
Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d
Doss [256]

Answer:

3.83

Step-by-step explanation:

Mean of x = Σx / n

Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2

Sum of square (SS) :

(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8

Mean of y = Σy / n

Mean of y = (101 + 89 + 48 + 21 + 47) / 5 = 61.2

Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8

df = n - 2 = 5 - 2 = 3

Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6

√(Σ(y - ybar)² / df) = √1449.6 = 38.074

Standard Error = √(Σ(y - ybar)² / df) / √SS

Standard Error = 38.074 / √98.8

Standard Error = 3.83

4 0
2 years ago
The price of XYZ stock fluctuates widely. In January it closed at $3.50 but In February it Closed at $2.25. However at the end o
son4ous [18]

Answer:

$3.583

Step-by-step explanation:

Given the monthly stock prices :

January = $3.50

February = $2.25

March = $5.00

The average monthly change in price of XYZ stock from. JANUARY through MARCH is;

(January + February + March) / 3

Average monthly change :

(3.50 + 2.25 + 5.00) / 3

$10.75 / 3

= $3.583

8 0
2 years ago
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