All categories

2 years ago

What is the equivalent of pi over 3 radians in degrees?

Mathematics

2 answers:

nikitadnepr [17]2 years ago

5 0

Answer:

The correct option is C) 60 degrees.

Step-by-step explanation:

Consider the provided radians

$\frac{\pi}{3}$

To convert from radians to degrees using the ratio $\frac{180}{\pi}$ .

Consider the provided radian measure and multiply it by $\frac{180}{\pi}$ .

$\frac{\pi}{3}=\frac{\pi}{3}\times \frac{180}{\pi}$

$\frac{\pi}{3}=\frac{180}{3}$

$\frac{\pi}{3}=60^0$

Thus the value of $\frac{\pi}{3}$ in degrees is 60°

Hence, the correct option is C) 60 degrees.

zalisa [80]2 years ago

3 0

60 degrees is the answer

You might be interested in

A road running north to south crosses a road going east to west at the point P. Car A is driving north along the first road, and

Anettt [7]

Answer:

D^2 = (x^2 + y^2) + z^2

and taking derivative of each term with respect to t or time, therefore:

2*D*dD/dt = 2*x*dx/dt + 2*y*dy/dt + 0 (since z is constant)

divide by 2 on both sides,

D*dD/dt = x*dx/dt + y*dy/dt

Need to solve for D at t =0, x (at t = 0) = 10 km, y (at t = 0) = 15 km

at t =0,

D^2 = c^2 + z^2 = (x^2 + y^2) + z^2 = 10^2 + 15^2 + 2^2 = 100 + 225 + 4 = 329

D = sqrt(329)

Therefore solving for dD/dt, which is the distance rate between the car and plane at t = 0

dD/dt = (x*dx/dt + y*dy/dt)/D = (10*190 + 15*60)/sqrt(329) = (1900 + 900)/sqrt(329)

= 2800/sqrt(329) = 154.4 km/hr

154.4 km/hr

Step-by-step explanation:

3 0

2 years ago

Determine whether the given signal is a solution to the difference equation. Then find the general solution to the difference eq

Ulleksa [173]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

The given equation is:

$y_{k + 2} + 8y_{k +1} - 9y_{k} = 20k + 12..(1)$

put,

$y_k = k^2\\\\y_{k+2}=(k+2)^2\\\\y_{k+1}=(k+1)^2\\\\$

$(k+2)^2+8(K+1)^2-9k^2 = 20k+12\\\\=20k+12= 20K+12\\\\$

hence y_k=k^2 is its solution.

Now,

$\to y_{k+2}+ 8y_k + 1 - 9y_k = 20k + 12$

the symbol form is:

$(E^2+8E-9)_{yk}=20k+12$

$\to m^2+8m-9=0\\\\\to m^2+(9-1)m-9=0\\\\\to m^2+9m-m-9=0\\\\\to m(m+9)-(m+9)=0\\\\\to (m+9)(m-1)=0\\\\\to m=-9 \ \ \ \ \ \ \ m=1\\$

The general solution is:

$y_k = c_1(-9)^k + c_2(`1)^k\\\\y_k =c_1(-9)^k+c_2$

The complete solution is:

$y_k=(y_k)_c+(y_k)_y\\\\y_k= c_1(-9)^k+c_2+k^2$

The answer is option b: $y_k = k^2 + c_1(-9)^k + c_2$

After solve the complete solution is:

$\bold{y_1=c_1(-9)^k+c_2+k^2.....}$

5 0

2 years ago

Consider a population list x with μx=10 and SDx = 1. A second population list, y, with μy=10 and SDy=2, is added to the first li

Basile [38]

Answer:

The combined standard deviation is 1.58114.

Step-by-step explanation:

The formula to compute the combined standard deviations of two different data sets is:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}$

Here $\mu_{c}$ is the combined mean given by:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}$

It is provided that the sample size is same for both the data sets, i.e. $n_{X} = n_{Y}=n$

Compute the combined mean as follows:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}\\=\frac{(n\times10)+(n\times10)}{n+n}}\\=\frac{20n}{2n}\\ =10$

Compute the combined standard deviation as follows:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}}\\=\sqrt{\frac{(n\times1^{2})+(n\times2^{2})+(n(10-10))+(n(10-10))}{n+n}}\\=\sqrt{\frac{n+4n}{2n} } \\=\sqrt{\frac{5n}{2n} } \\=\sqrt{\frac{5}{2}} \\=1.58114$

Thus, the combined standard deviation is 1.58114.

3 0

2 years ago

Which of the following is not a characteristics of a plane?

xeze [42]

So b is the correct answer

5 0

3 years ago

Determine the percent of change. Round to the

Goshia [24]

Answer:

DECREASE

Step-by-step explanation:

Not sure

But Hope It Help

5 0

2 years ago