Question

Need help on math question thanks A) 0.303 B) 0.435 C) 0.406 D) 0.154

Answer 1

Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

Explanation:-

Given data

                      Brown           Blue           Hazel           Green

Females           13                  4                  6                   9          

Males                10                  2                 9                   12

Let 'B' be the event of brown eyes

Total number of males n(M) = 33

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$

From table the brown eyes from males = 10

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

Final answer:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$