Can someone help me with this problem? Thank you!
1 answer:
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Answer:
See Below.
Step-by-step explanation:
In the given figure, AP = BP = PC.
And we want to prove that ∠ABC is a right angle.
Since AP = BP and BP = PC, we can create two isosceles triangles: ΔAPB and ΔCPB.
By the definition of isosceles triangles, in ΔAPB, ∠PAB and ∠PBA are equivalent. Let the measure of each of them be <em>x°</em>.
Likewise, in ΔCPB, ∠PCB and ∠PBC are equivalent.
And since AP = BP = PC, each of the angles∠PCB and ∠PBC will also be equivalent to <em>x°.</em>
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And since the sum of the interior angles of a triangle total 180°, we acquire:
Since they are all equivalent:
Hence:
∠ABC is the sum of ∠PBA and ∠PBC, each of which measures 45°. Hence:
Geometric is
an=nth term
a1=first term
r=common ratio
n=which term
commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor
the nth term is
an=nth term
a1=first term
r=common ratio
n=which term
commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor
the nth term is