Answer:
m∠AMO ≈ 54.7°
AΔANM = 486√3
Step-by-step explanation:
The edges are congruent, so all four faces are congruent equilateral triangles. We'll say the length of each edge is 2r.
The height of the pyramid h is given to be 36.
The perpendicular distance from O to line MP is called the apothem (a). Using 30-60-90 triangles, b = 2a and r = a√3.
Use cosine to find m∠AMO.
cos(∠AMO) = b / (2r)
cos(∠AMO) = (2a) / (2a√3)
cos(∠AMO) = 1 / √3
m∠AMO ≈ 54.7°
Use Pythagorean theorem to find the apothem.
(2r)² = b² + h²
(2a√3)² = (2a)² + 36²
12a² = 4a² + 1296
8a² = 1296
a² = 162
a = 9√2
So the edge length is:
2r = 2√3 (9√2)
2r = 18√6
The area of the equilateral triangle ΔANM is half the apothem times the perimeter:
A = ½aP
A = ½ (9√2) (3 × 18√6)
A = 243√12
A = 486√3
Answer:
i am gonna say D
Step-by-step explanation:
because well you don't what the total or the outcome is
correct me if i am wrong
Answer:


Detailed steps:
We know that the number of total events is

and that the probability of a certain event E (for example, "<em>the enemy drops two objects</em>") is computed as the number of times event E occurred, divided by the total of events N=80.
Then:


and

We can verify by checking that adding all probabilities sums up to one.
Since the radius of an object is half of the diameter, your equation and answer would be: 1.39 million divided by 2 = 695,000 km.