H = - 16 t² + 36 t + 10
The maximum height of the ball is at the vertex of the parabola.
t = - b / 2 a
t = -36/-32
t = 1.12 s
The maximum height of the ball:
h max = - 16 * 1.12² + 32* 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =
= - 20.0704 + 45.84 = 25.7696 = 25.77 m
Answer:
m∠QTR = 98°
Step-by-step explanation:
From the picture attached,
Radii of the circle are TQ and TR measuring equal lengths.
Therefore, ΔTQR is a isosceles triangle.
Opposite angles of the equal sides will be equal in measure.
m∠RQT = m∠TRQ = 41°
By angle sum theorem,
m∠RQT + m∠TRQ + m∠QTR = 180°
41° + 41° + m∠QTR = 180°
m∠QTR = 180° - 82°
= 98°
Therefore, m∠QTR = 98°
I may be wrong but I think it would be D, Since (even with the rounded edges) theres only 4 defined sides.
We are given the probability of rain tomorrow of 60 % and a 40% chance of wind and rain. we are asked for the probability that it is windy, given that it is rainy. The formula that should be used is the quotient of the probability with "and" over the probability of the rain only. Hence, <span>P[W U R ] / P [R] = 0.4 / 0.6 = 2/3 = 67%</span>
Services.
Since GDP is an estimate of everything produced or provided in a certain amount of time.
