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AveGali [126]
3 years ago
14

10 times as much as what is 1/10 of 900

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0
The answer should be 9, hope that helped ‘
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Two inches is cut from a board. The remaining board is 10 inches long. Write an equation to represent the situation.
Gemiola [76]

Answer:

12-2=10

Step by step explanation:

4 0
2 years ago
Marcy played the piano for 45 minutes. She stopped playing at 4:15 p.m. At what time did she start playing the piano?
fiasKO [112]
Well, first off 1 hr =60 minutes. 60 min - 45 min = 15 minutes extra. what is one hour before 4:15? 3:15! Add the subtracted 15 minutes to get 3:30... Hope this helps
4 0
3 years ago
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A lawn mower company wants to show how much time a homeowner can save by using a ride-on lawn mower instead of a push lawn mower
DanielleElmas [232]
A. F
b. T
c. T
d. T

1.5 Acres 2 Acres

42.5 ( 1.5 ) + 15 = 78.75 | 42.5 ( 2 ) + 15 = 100

78.5 ( 1.5 ) + 5 = 122.75 | 78.5 ( 2 ) + 5 = 162
6 0
1 year ago
Exercise 11.21) Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad ba
stiv31 [10]

Answer:

Step-by-step explanation:

Hello!

The researcher suspects that the battery life between charges for the Motorola Droid Razr Max differs if its primary use is talking or if its primary use is for internet applications.

Since the means for talk time usage (20hs) is greater than the mean for internet usage (7hs) the main question is if the variance in hours of usage is also greater when the primary use is talk time.

Be:

X₁: Battery duration between charges when the primary usage of the phone is talking. (hs)

n₁= 12

X[bar]₁= 20.50 hs

S₁²= 199.76hs² (S₁= 14.13hs)

X₂: Battery duration between charges when the primary usage of the phone is internet applications.

n₂= 10

X[bar]₂= 8.50

S₂²= 33.29hs² (S₂= 5.77hs)

Assuming that both variables have a normal distribution X₁~N(μ₁;σ₁²) and X₂~N(μ₂; σ₂²)

The parameters of interest are σ₁² and σ₂²

a) They want to test if the population variance of the duration time of the battery when the primary usage is for talking is greater than the population variance of the duration time of the battery when the primary usage is for internet applications. Symbolically: σ₁² > σ₂² or since the test to do is a variance ratio: σ₁²/σ₂² > 1

The hypotheses are:

H₀: σ₁²/σ₂² ≤ 1

H₁: σ₁²/σ₂² > 1

There is no level of significance listed so I've chosen α: 0.05

b) I've already calculated the sample standard deviations using a software, just in case I'll show you how to calculate them by hand:

S²= \frac{1}{n-1}*[∑X²-(∑X)²/n]

For the first sample:

n₁= 12; ∑X₁= 246; ∑X₁²= 7240.36

S₁²= \frac{1}{11}*[7240.36-(246)²/12]= 199.76hs²

S₁=√S₁²=√199.76= 14.1336 ≅ 14.13hs

For the second sample:

n₂= 10; ∑X₂= 85; ∑X₂²= 1022.12

S₂²= \frac{1}{9}*[1022.12-(85)²/10]= 33.2911hs²

S₂=√S₂²=√33.2911= 5.7698 ≅ 5.77hs

c)

For this hypothesis test, the statistic to use is a Snedecors F:

F= \frac{S_1^2}{S_2^2} *\frac{Sigma_1^2}{Sigma_2^2} ~~F_{n_1-1;n_2-1}

This test is one-tailed right, wich means that you'll reject the null hypothesis to big values of F:

F_{n_1-1;n_2-1; 1-\alpha }= F_{11;9;0.95}= 3.10

The rejection region is then F ≥ 3.10

F_{H_0}= \frac{199.76}{33.29} * 1= 6.0006

p-value: 0.006

Considering that the p-value is less than the level of significance, the decision is to reject the null hypothesis.

Then at a 5% level, there is significant evidence to conclude that the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for talk is greater than the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for internet applications.

I hope this helps!

8 0
2 years ago
Use the least common denominator to write an equivalent fraction for each fraction. 5/6 and 2/9
olchik [2.2K]
5/6 and 2/9......least common denominator is 18
so 5/6 = 15/18 and 2/9 = 4/18

1/12 and 3/8...least common denominator is 24
so 1/12 = 2/24 and 3/8 = 9/24

5/9 and 2/15...least common denominator is 45
so 5/9 = 24/45 and 2/15 = 6/45
3 0
3 years ago
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