Wx+yz=bc
minus wx on both sides
yz=bc-wx
dividing 'y' on both sides
Hence,
z=(bc-wx)/y
Here is what you need.
Hope it helped
The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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Answer: a
Step-by-step explanation:
16/21 is your answer
You can take a 2 out of both numbers to get your answer
I hope this helped! :)
Step-by-step explanation:
1. How many terms are in the expression?
The terms are sorted by looking at the sing/indicator in front of them. For this expression there are 4 terms
13x, -2y, -5x, and 8
2. Which terms are “like terms”?
13x and -5x are like terms.
3. Are there any constants? If so, what are they?
Yes there is a constant terms and it's 8
4. What are the variables in the expression?
The variables in this expression are x, and y
5. What are the coefficients in the expression?
Coefficients is the number in front of variables in this expression the coefficients are 13, -2, and -5