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Ainat [17]
3 years ago
5

Find the surface area of the prism. Enter your answer in the box. WILL GIVE BRAINLIEST

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

Answer:

252 square m

Step-by-step explanation:

Surface area of prism

= 2(6 \times 3 + 3 \times 12 + 12 \times 6) \\  = 2(18 + 36 + 72) \\  = 2 \times 126 \\  = 252 \:  {m}^{2}

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In circle F with m∠EFG=54m∠EFG=54 and EF=19
elena-14-01-66 [18.8K]

Answer:

17.907082 unit

Step-by-step explanation:

According to the Question,

Given, A circle with centre F, ∠EFG=54 and EF=19 .

length of arc EG = Radius(EF) × ∠EFG(in Radian)

  • We Know, 1 degree = 0.0174533 Radian
  • 54 degree = 0.942478 Radian

length of arc EG = 19 x 0.942478 ⇔ 17.907082 unit

(For Diagram please find in attachment)

3 0
3 years ago
Which of the following is a polynomial with roots
PtichkaEL [24]
a(x-x_1)(x-x_2)(x-x_3)\\\\x_1=-\sqrt3;\ x_2=\sqrt3;\ x_3=-2;\ a=1\\\\subtitute\\\\(x+\sqrt3)(x-\sqrt3)(x+2)=(x^2-3)(x+2)\\\\=\boxed{x^3+2x^2-3x-6}\to\fbox{B.}
5 0
3 years ago
Read 2 more answers
Question 1<br><br> Which of the following is NOT linked to cardiovascular disease
Anestetic [448]
Unsaturated fat is the correct answer
4 0
3 years ago
In a​ lottery, the top cash prize was ​$642 ​million, going to three lucky winners. Players pick five different numbers from 1 t
kramer

Answer:

\frac{10}{53 \times 46 \times 26}

Step-by-step explanation:

The probability of matching the number drawn on the gold ball is

\frac{1}{46}

The number of possible pairs of numbers from 1 to 53 is

\binom{53}{2}  =  \frac{53 \times 52}{2}  = 53 \times 26

Choosing 5 numbers, you are choosing 10 different pairs:

\binom{5}{2}  =  \frac{5 \times 4}{2}  = 10

Therefore the probability of correctly matching the drawn pair is

\frac{10}{53 \times 26}

Thus, the probability of winning (matching the pair AND the gold ball) is

\frac{10}{53 \times 46 \times 26}

4 0
3 years ago
Use inductive reasoning to describe the pattern of each sequence. Then find the next two terms. 1, 2, 5, 6, 9,
juin [17]
It looks like the first 1 is the first problem, problem #1. (because of the period)
If this is the case, then the second sequence is 1, 0, -1, ...
1-1=0
0-1=-1
-1-1=-2
-2-1=-3
-3-1=-4
The sequence would then be 1, 0, -1, -2, -3, -4, ...
5 0
3 years ago
Read 2 more answers
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