3(m + 5 + 9m)
A.
(1) 3m + 15 + 27m
(2) 3(10m + 5)
B. 3(m + 5 + 9m)....distributive property
(3 * m) + (3 * 5) + (3 * 9m) =
3m + 15 + 27m
C. 3(m + 5 + 9m) = 3(10m + 5)......m = 1
3(1 + 5 + 9(1) = 3(10(1) + 5)
3(1 + 5 + 9) = 3(10 + 5)
3(15) = 3(15)
45 = 45
Answer:
C: The speed increases from A to F
Step-by-step explanation:
Check each node A to F including A and F.
B is higher than A, C is higher than B, ...
This is true for all of them, so it is increasing.
V(t) = 2t^2 - 3t - 3
for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3
at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2
1/2 because it's 2 times smaller
20 possibilities based on this as a combination not a permutation, 6 nCr 3 = 20
