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Shtirlitz [24]
2 years ago
14

London has 3 meters of wood that he is using to make a small fence around his garden. If his fence has 5 sections, how wide is e

ach section?
Mathematics
1 answer:
salantis [7]2 years ago
3 0

Answer:

60cm

Step-by-step explanation:

total length of wood = 3m

number of sections = 5

width of each section = 3/5 = 0.6 m

= 60cm

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Answer:

Slope: 1/2.5

Y-intercept: -1

Step-by-step explanation:

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2 years ago
-6 + 4 = -4{ 2y + 2} what is the value of x
NikAS [45]

the Answer is :

-3/4 =y

8 0
3 years ago
Read 2 more answers
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
4 years ago
Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa
inessss [21]

Answer:

a) 0.4164

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Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

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z=\frac{12.04 - 18.8}{2} \\z=-3.38

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

z=\frac{18.38 - 18.8}{2} \\z=-0.21

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

P=41.68-0.036\\P=41.64\%\ or\ 0.4164

6 0
3 years ago
A square has an area that is less than 100m^2. What is a reasonable range for the graph of the square side?
bezimeni [28]
The area of the square is obtained by taking the square of the length of one side. Since it is said that the area of the square is less than 100 m^2, taking the square root of that where: sqrt (100) = 10, the side of that square should be less than 10 as well. Among the choices, D. 0 <y <10 (where y = length of side of square) is the correct answer.
3 0
3 years ago
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