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nataly862011 [7]

3 years ago

11

A flower shop sold 2,450 flowers in a month. If 60% of the flowers the store sold were roses, how many roses did the store sell

in a moth?

2 answers:

Sergio [31]3 years ago

6 0

Multiply 2,450 flowers by 60%.

2,450 * 0.60 = 1,470

The flower shop sold 1,470 roses in a month.

puteri [66]3 years ago

3 0

1470 of the 2450 flowers were roses.

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2 years ago

Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n

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The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

$a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\$

$When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\$

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

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