The price elasticity of demand of the pen will be -0.2.
<h3>How to compute the elasticity?</h3>
The demand and supply schedule will be:
Price Qd. Qs
$10. 250. 100
$20. 200. 90
$30. 180. 80
The price elasticity of demand from $1 to $2 will be:
= Percentage change in quantity demanded/percentage change in price
Percentage change in quantity demanded will be:
= (200 - 250)/250 × 100
= -20%
Percentage change in price will be:
= (20 - 10)/10 × 100
= 100%
Therefore, the elasticity of demand will be:
= -20/100
= - 0.2
The value gotten illustrates an inelastic demand.
In order to increase the total revenue, the price can be reduced as it will lead to more sales.
Learn more about PED on:
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<u>Complete question:</u>
Choose any product or service. Create the demand and supply schedule.
Calculate just one PED.
Is the demand elastic or inelastic?
What price change would you recommend to increase TR?
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
1060.5263157 etc your teacher prob tells you to round
Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor):
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4):
![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1):
![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.
X(x - 2) = 4 [upon multiplying and moving the 4 becomes x² - 2x - 4 = 0] x(2x + 3) = 12 [upon multiplying and moving the 12 becomes 2x² - 3x - 12 = 0] 3x(x + 8) = -2 [upon multiplying and moving the -2 becomes 3x² + 24x + 2 = 0]
