Answer:

Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner
is:

where :
(a and b are the length and the breath of the rectangle respectively )


![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)

Thus; the moment of inertia of the lamina about one corner is 
The answer would be a 1 Liter bottle, because a liter is 33 oz rounded and and Elgin millimeter container is 25 oz.
If you would like to solve y = x - 4 and 2 * x + y = 5, you can do this using the following steps:
y = x - 4
2 * x + y = 5
_____________
2 * x + (x - 4) = 5
2 * x + x = 5 + 4
3 * x = 9 /3
x = 9 / 3
x = 3
y = x - 4 = 3 - 4 = -1
The correct result would be x = 3 and y = -1.