I think its d !! I’m not sure
Answer:
C. The typical value is greater in set . The spread is greater in set A.
Step-by-step explanation:
Set A data is all over the place meanwhile set b data is clumped in one spot. This means Set A data has its data more spread. Then the value is greater in set B since the arrow is on 8.5 while in set A it is on 4.
Mr.Moore will read 67 pages on Sunday. The pattern will continue each day by 12. So on Friday he will have 53 pages read. On Saturday he will have 60 Pages read. And on Sunday he will have 67 pages read. :)
Answer:
Area = πr², where "r" is some distance "y" and/or the function "(1/6)x"; depending on the situation
Step-by-step explanation:
If I'm picturing this correctly, you'll have conical shape after revolving the function about the x-axis. If you took some generic slice and wanted to find the area of the resulting cross-section, then you would have a circle whose radius is some arbitrary value of the line that matches the slice.
For example:
y = (1/6)x right?
If you took a slice at x = 2, then the radius of the resulting cross-sectional circle would be equal to y = (1/6)•2 =1/3.
From here you just plug it into the area of a circle, πr², to get an area of π/3.
Except with an integral you need to take all the points on the interval, so the radius comes out to be the function itself.
Assuming your integral is in terms of dx, r=y. But in order to integrate in terms of dx you must replace "y" with its function (1/6)x. So ultimately r=(1/6)x and Area = π(1/6)x.
