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3 years ago

Whats the answer again plz I really need the help

Mathematics

2 answers:

horsena [70]3 years ago

6 0

Is there a picture to the problem?

Illusion [34]3 years ago

4 0

What is the question ill try to help

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In the diagram below secants PT & PU have been drawn from exterior point P such that the four arcs intercepted have the foll

fiasKO [112]

Answer:

x = 30°
RS = 30°, SR = TU = 120°, UR = 90°
∠P = 45°
∠UTS = 60°

Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

x + 4x +4x +3x = 360°

12x = 360°

x = 30°

(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

RS = 30°
ST = 120°
TU = 120°
UR = 90°

(c) Angle P is half the difference of arcs TU and RS:

∠P = (TU -RS)/2 = (120° -30°)/2

∠P = 45°

(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

∠UTS = 120°/2 = 60°

4 0

3 years ago

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the d

lesya [120]

Answer:

segment EH and segment E prime H prime both pass through the center of dilation.

Step-by-step explanation:

Center of dilation is point (0.1), same as H. Both, E(0,5) and H(0,1) are placed over y-axis, then E' and H' are also located at y-axis.

After dilation, H' is placed at (0,1) because it coincides with the center of dilation

Distance between E and center of dilation is 4 units, then E' should be at 4*3=12 units from the center of dilation and over y-axis. Therefore, E' is placed at (0, 13)

So, segment E'H' goes from (0,1) to (0,13), and pass through the center of dilation, like segment EH.

4 0

3 years ago

What is the midpoint of EC ?

sladkih [1.3K]

Given:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

Midpoint of EC:

The midpoint of EC can be determined using the formula,

$Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

$Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})$

Simplifying, we get;

$Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})$

Dividing, we get;

$Midpoint=(t+p,r)$

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

4 0

3 years ago

A cylindrical tank with a radius of 12 inches and a height of 20 inches is full of water. Does the tank have enough water to fil

Reptile [31]

Answer:

Yes, it can.

Step-by-step explanation:

To know if you can fill all the water balloons with the tank, the first thing is to calculate the volume of each one.

Volume of the tank, is a cylinder, whose volume is given as follows:

Vc = Pi * Rc ^ 2 * h

The radius of the cylinder has a value of 12 inches and the height of 20 inches. Thus:

Vc = 3.14 * (12) ^ 2 * 20 = 9043.2 inches ^ 3

Now, the volume of each globe that is a sphere is given by the following equation:

Ve = (4/3) * Pi * Re ^ 3

Being the radius of the sphere of 2, we have to:

Ve = (4/3) * 3.14 * 2 ^ 3 = 33.5 inches ^ 3

Now to know if you can fill all the balloons, we calculate the volume ratio of the tank and a balloon.

Vc / Ve = 9043.2 /33.5 = 269.95

Therefore, it can fill the 250 balloons because it has the capacity to carry approximately 269 balloons.

8 0

3 years ago

Read 2 more answers

6 = z/4.5 please answer

Veseljchak [2.6K]

Answer: z= 1.3

Divide both side by 4.5

6 0

3 years ago