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faltersainse [42]
3 years ago
14

Let x1, . . . , xn be independent exponential random variables having a common parameter λ. determine the distribution of min(x1

, . . . , xn)
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Given fx (x) = λe^λx

Fx (x) = 1 – e^-λx      x…0

To find distribution of Min (X1,….Xn)

By applying the equation

fx1 (x) = [n! / (n – j)! (j – 1)!][F(x)]^j-1[1-F(x)]^n-j f(x)

 

For minimum j = 1

[Min (X1,…Xn)] = [n!/(n-1)!0!][F(x)]^0[1-(1-e^-λx)]^n-1λe^-λx

= ne^[(n-1) λx] λe^(λx)

= nλe^(-λx[1+n-1])

= nλe^(-nλx)

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To cover a rectangular region of her yard, Penny needs at least 155 square feet of sod. The length of the
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<u><em>To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?</em></u>

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<u><em>L=length=15.5 ft; W=width; A=area=>170.5 sq ft</em></u>

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<u><em>L*W=>170.5 sq ft Divide each side by L</em></u>

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5 0
2 years ago
What is the measure of ABC?<br><br> A 44°<br> B 88°<br> C 176°<br> D 92°
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Answer: C) 44 degrees

Step-by-step explanation:

44

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<img src="https://tex.z-dn.net/?f=2%28x%20-%208%29%20%2B%204x%20%3D%206%28x%20-%202%29%20-%204" id="TexFormula1" title="2(x - 8)
Flauer [41]

In this question, you're solving for x.

Solve for x:

2(x - 8) + 4x = 6(x - 2) - 4

Distribute the 2 to the variables inside the parenthesis.

2x - 16 + 4x = 6(x - 2) - 4

Distribute the 6 to the variables inside the parenthesis.

2x - 16 + 4x = 6x - 12 - 4

6x - 16 = 6x - 12 - 4

6x - 16 = 6x - 16

Subtract 6x from both sides

-16 = -16

Add 16 to both sides

0 = 0

Answer:

All real numbers and solutions

8 0
3 years ago
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