What type of selection leads to increased phenotypic and genetic variation?
2 answers:
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Answer:
Since the gene that transmits hemophilia is linked to the X chromosome (), for a couple to have a hemophiliac daughter, the father must present the disease and the mother must be a carrier. Therefore, the parents' genotypes are
and
, while the daughter and son genotypes are
and XY, respectively
Explanation:
An X-linked recessive gene -as in the case of hemophilia- will only be expressed in males with the affected X chromosome or in females who are homozygous for that gene.
- A healthy man and a carrier woman can have healthy, hemophilic sons, while half of the daughters could be carriers.
- A haemophiliac man and a healthy woman could have healthy sons and carrier daughters.
- <em>A haemophiliac man and a carrier woman (as in the case above) can have healthy sons, while daughters can be carriers or haemophilics.</em>
The cross between the hemophilic father and the carrier mother can be seen in the following diagram:
Alleles Y
Y
X X XY
Where the possibility of having a healthy son and at least one daughter with hemophilia is evident.
Learn more:
Sex linked inheritance brainly.com/question/11839068