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SpyIntel [72]
3 years ago
5

Jones Electric Motors uses a Kanban system to make motors for several garage door companies in the southeastern United States. T

he daily demand for motor housings used in manufacturing is 100 units. The average waiting time for a container of parts is 0.2 day. The processing time for a container of housings is 0.1 day, and a container holds 5 housings. If Jones wishes to use a 10% policy variable, how many containers are needed
Business
1 answer:
Elis [28]3 years ago
7 0

Answer:

7 kanban containers are required

Explanation:

Given the following information :

Average Waiting time for containers = 0.2 days

Average processing time = 0.1 days / container

Daily usage (Demand rate) = 100 per day

Container capacity = 5 housings

Policy variable ( Alpha) = 10% = 0.1%

The required number of Kanban containers required by Jones Electric Motor can be calculated thus :

[Number of containers(x) * container size] = (Demand rate (waiting time + processing time)*(1 + alpha))

x * 5 = (100 * (0.2 + 0.1)*(1 + 0.1))

5x = [100 * (0.3)*(1.1)]

5x = [100 * 0.33]

5x = 33

x = 33 / 5

x = 6.6 containers

x = 7

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