Y = (-1/9).x + 4
The slope m of the line perpendicular to y = (-1/9).x + 4 is equal to 9:
(if the product of 2 slopes = - 1, then the 2 lines are perpendicular)

y = 9x + b, Since it passes by the point (-1,0) , then:
0= 9(-1) + b and b = 9
Final equation:

y = 9x+9

6 0

3 years ago

2-2x2-(39 divided by 1)+2+9

artcher [175]

-30 is the answer for your question

6 0

3 years ago

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

Oxana [17]

Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$

5 0

2 years ago

For the function f(x)=3(x-1)^2+2, identify the vertex,domain, and range -The vertex is (1,2), the domain is all real numbers, an

sdas [7]

Answer:

The function is...f(x)=(-1,-2)

Step-by-step explanation:

5 0

2 years ago

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