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Blizzard [7]
3 years ago
15

What is 7/10 equivalent to write the answer in fractions

Mathematics
1 answer:
Romashka [77]3 years ago
8 0
7/10 is equivalent to 3.5/5 is one
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Please answer this question now
Sever21 [200]

Answer:

82 degrees

Step-by-step explanation:

Measure of arc ABC = 86*2 = 172 degrees.

Measure of arc DC = 360 - (145+172) = 360-317 = 43 degrees.

Measure of arc BCD = 121+43 = 164 degrees.

Measure of angle A = 164/2 = 82 degrees

8 0
3 years ago
Read 2 more answers
The length of the table is 9 feet . Express the length in inches
diamong [38]

Answer:

the length of the table is 108 inches

4 0
3 years ago
Read 2 more answers
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\
A_x=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =60
\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\
-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\
A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =120
\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]
\\\\\\
A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\
-------------------------------\\\\
\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
3 years ago
2. Kelsea needs a test average of at least 90 to get an "A-" this marking period in math. Her three test grades
Luda [366]

Answer:

<u>Equation:  87 + 91 + 86 + x = 360</u>

<u>Solution: 264 + x = 360</u>

<u>x = 360 - 264</u>

<u>x = 96</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

First three Kelsea's test grades : 87, 91 and 86

2. What score must she get on her fourth test to receive at least an A- ?

Define variable:  x that represents the grade needed by Kelsea on her fourth test to receive at least an A-

Equation:  87 + 91 + 86 + x = 360

Solution: 264 + x = 360

x = 360 - 264

x = 96

<u>Now you can understand if the previous work you did is correct</u>

6 0
3 years ago
Solve the proportion: 12/16=9/48x
ivanzaharov [21]

Hey there

the answer is

x=4

thank you

    OFFICIALLYSAVAGE2003

5 0
3 years ago
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